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The barber paradox solved

Gregory September 18, 2020 at 04:48 16800 views 47 comments
The barber shaves those and only those who do not shave themselves

So there are perhaps people who do not shave themselves whom he does not shave. And those who shave themselves he does not shave. But he can't shave himself because he shaves only those who do not shave themselves. So anyone can shave the barber except himself

Solved?

Comments (47)

Outlander September 18, 2020 at 05:12 #453350
Quoting Gregory
The barber shaves those and only those who do not shave themselves


Apparently not anyone.

Also. This thread in a nutshell.

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Pfhorrest September 18, 2020 at 05:13 #453351
Quoting Gregory
But he can't shave himself because he shaves only those who do not shave themselves.


Therefore he does not shave himself, making him the kind of person who he does shave.

Therefore he does shave himself, making him the kind of person who he does not shave.

Therefore he does not shave himself ...


That's why this is a paradox.
Streetlight September 18, 2020 at 05:15 #453352
Not at all. The question is: Does the barber shave himself or not? Your 'solution' doesn't address this at all.
Gregory September 18, 2020 at 14:40 #453417
The barber cannot shave himself because he shaves ONLY those who do NOT shave themselves.

"Therefore he does not shave himself, making him the kind of person who he does shave." He shaves others

"Therefore he does shave himself, making him the kind of person who he does not shave." No he doesn't shave himself. He can't because of the paradox

Philosophim September 18, 2020 at 14:47 #453420
Reply to Gregory

The trick in the sentence is that it implies its talking about people other than himself. If we put the true intention of the sentence together we get:

The barber only shaves others who do not shave themselves.

Now, if we add in the idea that this also includes him, there is no paradox, we just realize the sentence contains a contradiction.

The barber only shaves others who do not shave themselves. The barber also shaves himself, because he does not shave himself.

The first sentence makes sense. The second sentence, which was attempted to be placed implicitly within the OP's sentence, reveals itself to be a nonsense statement when made implicit. If you combine the first and the second sentence together, then the contradictory part of the second sentence makes the combined sentence false, but not a paradox.
Gregory September 18, 2020 at 15:07 #453425
Reply to Philosophim

There is no paradox, but contradiction instead? Nop. He does not shave himself because he shaves only those who not shave themselves. The paradox is one sentence: the barber shaves those and only those who do not shave themselves.
Gregory September 18, 2020 at 15:12 #453429
The barber shaves those who do not shave themselves. We add "and only those" because it does not say enough otherwise
Philosophim September 18, 2020 at 20:04 #453485
Reply to Gregory

The difference between a paradox and a poorly constructed sentence can be tricky. A paradox would be the result of a logical concept taken to its conclusion. For example, someone is able to time travel, and ends up accidently killing their mother before they were born. A paradox denotes something can happen, but if something is done within that action, it could negate the possibility of being able to do that action to begin with. This is a contradiction, but it is a contradiction that states limits within action A that do not allow it to do action B.

A poorly constructed sentence is written as a contradiction. Poor sentences often come about because there is implicit cultural understanding that confuses the issue. That's why I broke the sentences down into explicit parts, removing the implicit assumptions that muddy the waters.

If you are saying that he shaves everyone who doesn't shave themselves, and also himself, then its fine. If you say that he shaves everyone who doesn't shave themselves, and himself, even though he doesn't shave himself, then its a contradiction. We can remove the first part about "other people", because its unnecessary. You cannot both shave, and not shave yourself. That's the contradiction, not a paradox. If you include a contradiction with extra sentence combinations, it still doesn't negate the fact of the contradiction.
EnPassant September 21, 2020 at 19:53 #454548
Shouldn't it be "The barber shaves Everyone who does not shave himself"? At any rate, this is a superficial 'paradox' because the statement is not, and cannot be true. It is a lie. Even in terms of set theory it is superficial because it assumes the is a "set of all sets..." but the entity that contains all sets is not and cannot be a set, yet it exists* so the assumption that this set exists is what causes the paradox. The entity that is 'all sets...' is an infinite set of sets, discussed here: https://thephilosophyforum.com/discussion/8334/russels-paradox
Michael September 21, 2020 at 20:10 #454556
Quoting Gregory
There is no paradox, but contradiction instead?


Paradoxes are contradictions. They're just often not obviously so.
Gregory September 21, 2020 at 22:30 #454626
It still seems to me if he shaves those, even everyone, who does not shave themselves, then he couldn't shave himself
Gregory September 21, 2020 at 22:30 #454628
Otherwise its too ambiguous to mean anything
Srap Tasmaner September 22, 2020 at 05:42 #454708
Reply to Gregory

Quoting Srap Tasmaner
Suppose we have a town with three men: a barber (B), a philosopher (P) who doesn't shave himself, and a mathematician (M) who does.

Now define a set R as all and only men who shave all and only men who don't shave themselves.

1. M is never a member of R because he shaves a man who shaves himself.
2. P can't be a member either because he doesn't shave himself, so he'd have to shave himself to be a member, but he doesn't.
3. What about B? He would have to shave P and not M. No problem. If he shaves himself, he'd be out, like M, but if he doesn't, he'd be out like P. So B can't be a member no matter what he does.

So R = { }. No one shaves all and only men who do not shave themselves, therefore the barber does not shave all and only men who do not shave themselves. The three cases are exhaustive, in fact: no one can be a member of R whether they shave themselves or not.
Gregory September 22, 2020 at 05:53 #454711
Number 2 is wrong. The philosopher doesn't shave himself so he is in the set of those who shave all those who do not themselves. You tried to add another loop Srap but it's the same paradox, which I already solved and I don't know why you guys don't get it. I read your post very slowly, slowing my heart rate, and it's clear this paradox is making something at of nothing
Gregory September 22, 2020 at 06:00 #454713
No one shaves all and "only men" who do not shave themselves? Do you realize this would affect empirical reality of this idiot paradox were true?
Srap Tasmaner September 22, 2020 at 06:18 #454715
Quoting Gregory
Number 2 is wrong. The philosopher doesn't shave himself so he is in the set of those who shave all those who do not themselves.


Let S be the set of all men who don't shave themselves.
P is a member of S.
To be a member of R, you have to shave all the members of S.
Since P is a member of S, to be a member of R he would have to shave himself.
But he doesn't.
Therefore P is not a member of R.
Michael September 22, 2020 at 06:20 #454716
Quoting Gregory
You tried to add another loop Srap but it's the same paradox, which I already solved and I don't know why you guys don't get it. I read your post very slowly, slowing my heart rate, and it's clear this paradox is making something at of nothing


Every person who shaves himself is named John. Every person who does not shave himself is named James. The barber shaves every person named James and doesn't shave anyone named John.

What is the barber's name?
MSC September 22, 2020 at 06:21 #454717
Quoting Gregory
The barber shaves those and only those who do not shave themselves

So there are perhaps people who do not shave themselves whom he does not shave. And those who shave themselves he does not shave. But he can't shave himself because he shaves only those who do not shave themselves. So anyone can shave the barber except himself

Solved?


No, not solved. Also a poor framing of the original problem.

There is a town. It has two laws about Barbers.
First law; Everyone has to be shaved by the barber.
Second law; No one can shave himself.

The solution is simple. The barber shaves himself. First law states "Everyone".

By way of the first law, the barber shaves no man who shaves himself, except himself because he is ultimately still accounted for when the word "Everyone" is used. He's by law logically exempt from the second law because he's the only barber in the town.

Now it's solved. It's just a logic puzzle.
MSC September 22, 2020 at 06:23 #454718
Next people will start believing a no-cat is a real animal based on descriptions about the number of tails it has as opposed to a real cat.
Gregory September 22, 2020 at 07:07 #454721
I don't know why you guys don't talk like adults
Gregory September 22, 2020 at 07:09 #454722
If there was really a paradox here it would affect material reality. I originally stated the paradox accurately so it could be understood as language works.
Gregory September 22, 2020 at 07:11 #454723
His name is James
Gregory September 22, 2020 at 07:16 #454725
Reply to Srap Tasmaner .

Your latest post is illogical. It has me have a "mad laugh" . I know what I need to know about logic. I have a full vision of it. Are you into math or just logic? Math is too tedious but I have a full vision of it too.
Michael September 22, 2020 at 07:16 #454726
Quoting Gregory
His name is James


The barber shaves every person named James (as per the third rule), and so if his name is James then he shaves himself. But if he shaves himself then his name is John (as per the first rule).
Gregory September 22, 2020 at 07:17 #454727
Gregory September 22, 2020 at 07:19 #454728
It's not a logical paradox. It's language game that's cleared up when you COMBINE language with logic
Michael September 22, 2020 at 07:19 #454729
Reply to Gregory Which part is bullshit? That he shaves himself because his name is James or that his name is John because he shaves himself?
Gregory September 22, 2020 at 07:21 #454731
Reply to Michael The

Dude, if you have one group doing something and another doing something, they are doing something. I didn't know you'd play a game that's idiotic
MSC September 22, 2020 at 07:22 #454732
Reply to Gregory Quoting Gregory
It's not a logical paradox. It's language game that's cleared up when you COMBINE language with logic


Dear gods people listen to Gregory! Gregory knows, be more like Gregory. Make it a fucking meme.

Still though Gregory, you could have framed it a little better for them.
Gregory September 22, 2020 at 07:22 #454733
Reply to MSC

I couldn't have
MSC September 22, 2020 at 07:27 #454734
Reply to Gregory Reply to Gregory You're smart enough, I'm sure you could have given the time. Sorry if it seemed like my original response came off as aggravated, it wasn't at you. Just the individuals trying to make a mountain out of a molehill and taking too long.
Michael September 22, 2020 at 07:28 #454735
Quoting Gregory
The

Dude, if you have one group doing something and another doing something, they are doing something. I didn't know you'd play a game that's idiotic


Part of your reply seems to be missing.

Which of these do you disagree with?

1. The barber shaves himself because his name is James
2. The barber's name is John because he shaves himself
TheMadFool September 22, 2020 at 07:30 #454737
Reply to Gregory @PfhorrestWhat if the barber is a woman? A prerequisite for the paradox is that the barber must have a beard; only then does the paradox enter the picture. no man, no beard and no beard, no paradox.
Gregory September 22, 2020 at 07:37 #454739
Many if not all of you are deliberately not talking normally. I tried my best to type this on a weird wonky tablet
MSC September 22, 2020 at 07:39 #454740
Reply to Gregory say what now big fudge? Many if not all? Where do I factor into this?
Gregory September 22, 2020 at 07:51 #454745
Reply to MSC

Thusly because you went with them in trying to force a contradiction
Gregory September 22, 2020 at 07:52 #454746
If logic has an inherent contradiction, and math is based on logic, than math is self refuting
Gregory September 22, 2020 at 07:55 #454747
If you want to find a contradiction, you'll find it. A real contradiction is Zeno's paradox. If you desire to create contradictions instead of discovering them, that is possible
MSC September 22, 2020 at 07:57 #454748
Reply to Gregory Okay I misunderstood you when you talked about language games. I thought you understood my answer. I didn't realise you had a misconception of what a paradox is and were conflating logic in math for logic in human culture. Sorry.
Gregory September 22, 2020 at 07:58 #454749
Reply to MSC

I'm not sure what you mean but you seem nice. I always try my hardest
Angie's Psycho-Logy September 22, 2020 at 08:04 #454753
If you spend all your time working on shaving others, when do you have time to work on shaving yourself? Who will shave your skull?
MSC September 22, 2020 at 08:14 #454754
Reply to Gregory Well, a linguistic paradox is when two ideas are thought of to be true at the same time even though their natures inherently negate each other. So if an argument has two of these sorts of ideas in them, the chances that one or both being true are diminished. One is definitely not true, one might be or might not be.

A mathematical paradox is a mathematical conclusion so unexpected that it is difficult to accept even though every step in the reasoning is valid. For example mathematical reasonings where every step is valid in an explanation of how 2+2 could possibly equal 5 is a mathematical paradox.

You're right about the logic, but you've made the mistake of treating a language game like a numbers game. The rules aren't the same. So neither is the definition of a paradox.

For example, a paradox in time, where you travel in time and encounter a past or future version of you is a mathematical paradox.

If time travel is possible in a given universe and you encounter another version of you then what should normally be 1, becomes 2. Mathematical paradox.

To explain the problem of the barber mathematically, it's just algebra.

Symbol for Barber, Symbol for everyone, Symbol for rules of culture on who gets to cut who's hair or shave who's beard.

Let me put it this way. If all Bs are a part of E and only B gets to do S, B must do S to E, because B is equal to E, B must also do S to B.

B is Barber
E is everyone
S is shave

Does that make a bit more sense? I hope I haven't made it more confusing for you.

MSC September 22, 2020 at 08:31 #454758
" you spend all your time working on shaving others, when do you have time to work on shaving yourself? Who will shave your skull?"

@Gregory Did you feel threatened at all by this comment from this extremely new account? I've sent a message to the moderators and this account. If anyone said this to my face I'd probably act pre-emptively. Way too dark and not funny if it's meant as a joke either.

Gregory September 22, 2020 at 09:15 #454766
I didn't feel threatened, but now that's it's pointed out, it is a weird first post
Gregory September 22, 2020 at 09:18 #454768
I am going to have to take a break from this thread for a week or more. If there is a true paradox here, I hope to find it when my head feels cooler. You guys did a great job. Thanks for all the help on this
Srap Tasmaner September 22, 2020 at 14:28 #454815
Quoting Gregory
If logic has an inherent contradiction, and math is based on logic, than math is self refuting


The contradiction is in claiming that there can be any such barber. There cannot. Just because you can string words together grammatically doesn't mean you're describing something that can actually be.

That's why I like framing the problem as figuring out who would be in the set of all such barbers. You find that such a set is necessarily empty because the conditions for being a member are inconsistent. You might as well define a set of all the numbers equal to 4 and equal to 5. There's no contradiction in that; you've just defined a set that's necessarily empty.
Amalac March 11, 2021 at 20:24 #509069
The barber (B), a philosopher (T) who doesn't shave himself, and a mathematician (M) who does.

We have all and only men who shave all and only men who don't shave themselves.

1. M is never a member of R because he shaves a man who shaves himself.
2. P can't be a member either because he doesn't shave himself, so he'd have to shave himself to be a member, but he doesn't.
3. What about B? He would have to shave P and not M. No problem. If he shaves himself, he'd be out, like M, but if he doesn't, he'd be out like P. So B can't be a member no matter what he does.

So R = { }. No one shaves all and only men who do not shave themselves, therefore the barber does not shave all and only men who do not shave themselves. The three cases are exhaustive, in fact: no one can be a member of R whether they shave themselves or not.
— Srap Tasmaner"


First things first, some things need to be clarified:

Are B, T and M each categorized/defined (for example when M is categorized as one who shaves himself), before the hypotetical shavings are done or after they are done? I'll asume first that it is after the shavings are done:

If M shaves himself, he shaves himself and can't be a member.

Does «The philosopher does not shave himself» mean: He hasn't shaved himself until know and never will? If so, by definition he can't ever shave himself, and therefore can never be a member since he can never shave someone who does not shave himself.

Since Srap says that the implication: if the philosopher shaved himself, then he would be a member is true, we'd have to say: if he shaved himself he would shave someone who does not shave himself. But if it were possible for him to shave himself, then he would in that case have shaved someone who shaves himself (since after he shaves himself, he is someone who shaves himself) and therefore he would not be a member. So the implication can't be true if P shaves himself.

However, it's impossible for him to shave himself by definition, and therefore he can never be a member. This means the implication «If he shaved himself, he would be a member» is true, since it could only be false if he both shaved himself and wasn't a member, which can never happen since the antecedent is impossible. So what Srap says up to this point appears correct if we interpret it like this.

Or does it mean: He hasn't shaved himself until know, but may shave himself in the future? If so, he would shave someone who shaves himself (since after he shaves himself, he is someone who shaves himself) and therefore not be a member. So this can't be what it means if Srap is right.

As for the barber: If he shaves himself he will shave someone who shaves himself (since after he shaves himself, he is someone who shaves himself) and therefore not be a member.

If he shaves M, if M already shaved himself before, then the barber would shave someone who shaves himself, and not be a member. If M hasn't shaved himself yet, then he would shave someone who doesn't shave himself, and be a member. So it must be the case that M already shaved himself in the past if Srap is right.

If B shaves P, then he shaves someone who doesn't shave himself, and is therefore a member of R.

This is problematic, because according to this interpretation since P does not shave himself, the barber would shave someone who does not shave himself, and therefore the barber would be a part of R, which contradicts what Srap says: that R is empty.

Nonetheless, this interpretation does show that if he shaves himself, he would not be a member of R.

Let's now assume they are caracterized *before* any of the hypotetical shavings used in the previous reasonings happen:

If M shaves himself, then if M shaved himself in the past, then he shaves someone who shaves himself and is not a member. This must be the case if Srap is right.

If he hasn't, then he shaves someone who doesn't shave himself (yet) and therefore is a member. This can't be right if Srap is right.

If P shaves himself, then he shaves someone who doesn't shave himself (yet) and therefore is a member. According to Srap, this too can't be the case.

Unless we include in the definition of P that he never will shave himself, in which case it's impossible for him to shave someone who does not shave himself, and therefore he can never be a member of R, and the implication “if P shaves himself, he would shave someone who doesn't shave himself (yet)” would once again be true because the ground/ antecedent is by definition always false. This must be right if Srap is right.

If the barber shaves himself, and if he hasn't shaved himself in the past, then he would be shaving someone who does not shave himself, since before he shaves himself he hasn't shaved himself. Therefore, he would be a member. This can't be the case if Srap is right.

If the barber shaves himself but has also shaved himself in the past, then he shaves someone who shaves himself, and is therefore not a member. This must be so, according to Srap.

If the barber shaves M, then if M shaved himself in the past, then he shaves someone who shaves himself and is not a member. This must be the case if Srap is right.

If M hasn't shaved himself in the past, then the barber would be shaving someone who does not shave himself, and therefore would be a member, which can't be the case according to Srap.

If B shaves P, then he shaves someone who doesn't shave himself, and is therefore a member of R.

And so we have the same problem as before.

So it seems that in either case R is not empty because the barber belongs to R.

Unless I made a mistake somewhere, of course.